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Vector Practice Test 2 ( Resolution of Vector )
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1 / 38
Which of the following is a correct statement about unit vector along a given direction?
Explanation:A unit vector is defined as a vector whose magnitude is exactly one. It is used only to indicate direction and not strength. Therefore it has magnitude one and points along a specific direction.
2 / 38
If a vector lies along the x-axis, its y-component is
Explanation:A vector along the x-axis makes angle 0° with that axis. Its entire magnitude lies along x, so projection on y-axis is zero. Hence for a vector along the x-axis the y-component vanishes.
3 / 38
A 10 N force acts at 0° with the x-axis. Its components are
Explanation:Angle 0° means the force lies exactly along the positive x-axis. So the whole magnitude is in the x-direction and none in the y-direction. Therefore components are 10 N along x and 0 N along y.
4 / 38
A vector of magnitude F making angle θ with the x-axis has an x-component equal to
Explanation:The x-component is the projection of the vector on the x-axis. In a right triangle, adjacent side to angle θ is given by magnitude times cosθ. So the x-component of the vector is F cosθ.
5 / 38
If a vector lies along the y-axis, its x-component is
Explanation:A vector along the y-axis makes angle 90° with the x-axis. The projection of such a vector on the x-axis is zero because cos90° = 0. So the x-component of a purely vertical vector is zero.
6 / 38
A force of 25 N acts at 180° to the x-axis. What is the magnitude of its x-component?
Explanation:
The x-component is Fₓ = F·cos θ = 25·cos 180° = 25·(–1) = –25 N, whose magnitude is 25 N.
7 / 38
A force vector F makes angle 30° with the positive x-axis. Its y-component is
Explanation:The y-component of a vector at angle 30° is F sin30°. Sin30° has value 1 / 2. Therefore the y-component of the force is F / 2.
8 / 38
If a vector has magnitude 13 units and components 5 units along x and 12 units along y, then
Explanation:For perpendicular components, magnitude of the vector is √(Ax² + Ay²). Using given components, √(5² + 12²) = √(25 + 144) = √169 = 13. So the components are consistent with the given vector magnitude.
9 / 38
A force of 20 N acts at 60° to the x-axis. What is the magnitude of its x-component?
The x-component is Fx = F·cos θ = 20·cos 60° = 20·0.5 = 10 N.
10 / 38
Resolving a vector into components is especially useful because
Explanation:When vectors are written as components along axes, each component behaves like a simple scalar quantity. Components along the same axis can be added or subtracted directly. This simplifies calculation of resultant vectors while preserving full vector information.
11 / 38
Which statement is true when a vector is resolved into components along coordinate axes?
Explanation:Components along axes are usually smaller than the original vector in magnitude. However, when combined vectorially, they give back the same original vector. So resolution does not change the vector, it just expresses it in another convenient form.
12 / 38
Resolution of a vector means
Explanation:Many problems become simpler when a vector is expressed in terms of simpler parts. This process of splitting a single vector into parts is called resolution of a vector. Usually these parts are chosen along convenient directions such as coordinate axes. So resolution means breaking a vector into components, not adding vectors.
13 / 38
A force of 10 N is acting along the x-axis. Which of the following is the magnitude of its y-component?
A force entirely along x has no y-component ⇒ 0 N.
14 / 38
A vector of magnitude 20 units makes an angle 60° with the positive x-axis. Its x-component is
Explanation:The x-component is given by magnitude multiplied by cos of the angle with x-axis. Here it is 20 cos60°.
=20 (1/2) =10 units
15 / 38
In two-dimensional motion, how many independent rectangular components does a vector have?
Explanation:Two-dimensional motion takes place in a plane with two perpendicular axes. A vector in this plane can be completely described by its x- and y-components. So it has two independent rectangular components.
16 / 38
A child pulls a box with a force of 200N at an angle of 60∘ above the horizontal. Then the horizontal and vertical components of the force will be:
17 / 38
Which of the following statements about components is correct?
Explanation:When a vector is resolved, it is expressed as the sum of simpler vectors along chosen directions. These simpler vectors are called components of the original vector. If the resolution is correct, their vector sum reproduces exactly the original vector in both magnitude and direction.
18 / 38
A vector A can be written in terms of unit vectors i and j as A = Ax i + Ay j. Here Ax and Ay represent
Explanation:Unit vectors i and j point along x- and y-axes respectively. Ax and Ay are scalar multipliers that give the length of A along each axis. Hence Ax and Ay are the scalar components of A along x and y directions.
19 / 38
For a vector of magnitude F at angle 45° with x-axis, its x- and y-components are
Explanation:At 45°, both cosine and sine have the same value 1 / √2. So x-component is F cos45° = F / √2. Similarly y-component is F sin45° = F / √2. Thus both components have equal magnitude F / √2.
20 / 38
If the components of a vector are Ax = –4 units and Ay = –3 units, the magnitude of the vector is
Explanation:Magnitude of a vector with components Ax and Ay is √(Ax² + Ay²). Here magnitude is √((-4)² + (-3)²). That equals √(16 + 9) = √25 = 5 units.
21 / 38
A force along the x-axis makes θ=0° with the x-axis, soFy = F·sin θ = 10·sin 0° = 10·0 = 0 N.
22 / 38
A force of 8 N acts at 45° to the x-axis. What is the magnitude of its x-component?
Fₓ = F·cos θ = 8·cos 45° = 8·(√2/2) = 4√2 N.
23 / 38
A 10 N force acts at 90° with the x-axis. Its components are
Explanation:Angle 90° means the force lies along the positive y-axis. So there is no horizontal component and full magnitude in vertical direction. Thus components are 0 N along x and 10 N along y.
24 / 38
Which one of the following is a necessary condition for resolving a vector into two components along given directions?
Explanation:A vector can be resolved along any two non-collinear directions. Non-collinear means the two directions are not along the same straight line. Perpendicular directions are a convenient special case, but not strictly necessary.
25 / 38
If a vector has magnitude F and its y-component is zero, then the angle it makes with the positive x-axis can be
Explanation:Zero y-component means the vector lies along the x-axis. Along positive x-axis the angle is 0°, and along negative x-axis it is 180°. So for zero y-component, the angle with positive x-axis is either 0° or 180°.
26 / 38
When resolving a weight vector of magnitude W acting vertically downward into components along horizontal and vertical directions, the horizontal component is
Explanation:Weight acts along the vertical direction. Horizontal direction is perpendicular to the direction of weight. Projection of a vector on a perpendicular direction is zero. So horizontal component of weight is zero.
27 / 38
A force vector F makes angle 30° with the positive x-axis. Its x-component is
Explanation:For a vector at angle 30°, x-component is F cos30°. cos30° is √3 / 2. So the x-component of the force is F √3 / 2.
28 / 38
If a vector makes an angle θ with the positive x-axis and its x-component is negative while y-component is positive, the vector lies in
Explanation:A negative x-component points towards the left. A positive y-component points upwards. Together they place the vector in the second quadrant of the x–y plane.
29 / 38
A vector in the xy-plane has components Ax = 8 units and Ay = 0 units. This vector
Explanation:A non-zero Ax with Ay equal to zero means there is only horizontal part. The vector lies completely along the x-axis. So it is a purely horizontal vector with no vertical component.
30 / 38
A vector of magnitude F making angle θ with the x-axis has a y-component equal to
Explanation:The y-component is obtained by projecting the vector on the y-axis. In the right triangle formed, the opposite side to angle θ is F sinθ. Therefore the y-component of the vector is F sinθ.
31 / 38
The most useful components of a vector in plane problems are usually taken along
Explanation:In two-dimensional motion we often use x- and y-axes at right angles to each other. Expressing a vector along these perpendicular axes gives two independent components. These perpendicular components can be handled with simple algebra and Pythagoras.
32 / 38
A force of 15 N acts at 90° to the x-axis. What is the magnitude of its x-component?
Fₓ = F·cos θ = 15·cos 90° = 15·0 = 0 N.
33 / 38
The magnitude of a vector whose components are Ax and Ay along two perpendicular axes is
Explanation:Components Ax and Ay act like the legs of a right-angled triangle. The original vector is represented by the hypotenuse of this triangle. By Pythagoras, magnitude of the vector is √(Ax² + Ay²).
34 / 38
If the components of a vector along x- and y-axes are equal and positive, the vector makes an angle
Explanation:Equal positive components mean Ax = Ay and both are greater than zero. Then tanθ = Ay / Ax = 1. So θ = tan⁻¹(1) = 45°, measured from the x-axis towards the y-axis.
35 / 38
The process of resolving a force at an oblique angle into horizontal and vertical components uses
Explanation:Horizontal component is given by F cosθ when θ is measured from the horizontal. Vertical component is F sinθ with the same angle definition. So resolution into horizontal and vertical components uses both sine and cosine.
36 / 38
The direction θ of a vector with components Ax and Ay (Ax > 0) relative to x-axis is given by
Explanation:In the right triangle for components, tanθ equals opposite over adjacent. Here opposite side is Ay and adjacent side is Ax. So tanθ = Ay / Ax and θ = tan⁻¹(Ay / Ax) when Ax is positive.
37 / 38
If a vector has components Ax = 0 and Ay < 0, its direction is
Explanation:Component Ax = 0 means there is no horizontal part of the vector. Ay < 0 means the vertical component points downward. So the vector lies along the negative y-axis.
38 / 38
A force of 12 N acts at 30° to the x-axis. What is the magnitude of its y-component?
Fᵧ = F·sin θ = 12·sin 30° = 12·0.5 = 6 N.
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